A uniform disc of radius R is put over another uniform disc of radius 2R made of same material having same thickness. The peripheries of the two discs touches each other. Locate the centre of mass of the system taking center of large disc at origin.
Text Solution
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At R/5 from the centre of the bigger disc towards the centre of the smaller disk.
Sol.
M 1 = π (2R) 2 × ρ M 2 = π (R) 2 × ρ x 1 = 0, x 2 = R
So , X cm = 
, X cm = 
= 
towards smaller disc
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